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You'd use , which links an ideal gas' volume to its temperature if pressure and number of moles are kept constant.

The mathematical formula is this

$V_1/T_1 = V_2/T_2$

In your case,

$V_1 = 8.0 L$,
$T_1 = 273.15 + 27 = "300.15 K"$, and
$V_2 = "12.0 L"$

Therefore,

$T_2 = V_2/V_1 * T_1 = "12.0 L"/"8.0 L" * "300.15 K" = "450 K"$

If pressure and number of moles are constant, an increase in volume means an increase in temperature and vice versa.

SIDE NOTE All you really need to know is the equation, PV = nRT, since you can apply it to all sorts of conditions; in your case, you'd get two equations to describe the two stages - once again, number of moles and pressure are constant

$PV_1 = nRT_1$ and $PV_2 = nRT_2$

DIvide these two equations and you'll get the expression for again

$V_1/V_2 = T_1/T_2$, or $V_1/T_1 = V_2/T_2$

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