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You have the stoichiometric equation, which tells you, unequivocally, that 2 equiv ethane reacts with 7 equiv dioxygen gas (alternatively 1 equiv ethane reacts with 3.5 equiv $O_2$).

$"Moles of ethane"=(2.5*g)/(30.1*g*mol^-1)=0.083*mol$.

$"Moles of dioxygen"=(170*g)/(32.0*g*mol^-1)=5.3*mol$.

There is a stoichiometric EXCESS of dioxygen gas.

Can you tell us how much carbon dioxide would be produced given complete combustion?

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