problems are all about moles, more specifically about moles of reactants.
Two two things to look out for in such cases are
Your tool of choice for problems, and for any problme, for that matter, is the , that is, the ratio between how many moles of each reatant are needed in order for the reaction to take place.
Let's say that you have a generic reaction
$"A" + color(red)(2)"B" -> "C" + "D"$
The stoichiometric coefficients that are placed in front of each reactant represent how many moles of each are needed. In this case, you have
This means that you have a
Simply put, regardless of how many moles of
With this in mind, you would go on to calculate how many moles of each reactant you have by suing their respective molar mass.
$"no. of moles" = "mass"/"molar mass"$
Once you have the number of moles of each reactant, compare them with the
Here's how you would do that. Let's say that those
Pick one of the two rectants, and check to see if you have enough number of moles of the other reactant. Let's pick
$1.5color(red)(cancel(color(black)("moles of A"))) * (color(red)(2)" moles of B")/(1color(red)(cancel(color(black)("mole of A")))) = "3 moles of B"$
This tells you that in order for all the moles of
Alternatively, we could have picked
$2.5color(red)(cancel(color(black)("moles of B"))) * ("1 mole of A")/(color(red)(2)color(red)(cancel(color(black)("moles of B")))) = "1.25 moles of A"$
In order for all the number of moles of
So, as a conclusion, in order to determine the limiting reagent, you must