What mass of $"potassium chloride"$ would result from the redox reaction of $"potassium chlorate"$? How is the reaction represented stoichiometrically?

Md Ariful Islam

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Md Ariful Islam

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Often a little $"manganese(IV) oxide"$ is added to these reactions, as an oxygen transfer reagent, i.e. a catalyst.

Given the , moles of $"potassium chloride"$ produced are CLEARLY equal to the moles of $"potassium chlorate"$ reacted. Agreed?

$"Moles of potassium chlorate"=(27*g)/(122.6*g*mol^-1)=0.220*mol$

And thus $"moles of potassium chloride"$

$=0.220*molxx74.55*g*mol^-1=??*g$

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