By definition, the empirical formula is the simplest whole numer ratio that defines constituent atoms in a species. Normally we are given percentages, and use this mass percent to determine the elemental composition. Here, we are explicitly given the molar ratios, i.e.
Let the mass of the 10 % alloy be $xcolor(white)(l)"lb"$. Then $20 color(red)(cancel(color(black)("lb"))) × 15 color(red)(cancel(color(black)("% Sn"))) + x color(red)(cancel(color(black)("lb"))) × 10 color(red)(cancel(color(black)("% Sn"))) = (20 + x) color(red)(cancel(color(black)("lb"))) ×...
1 Answers 1 viewsThe idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then...
1 Answers 1 viewsA compound's empirical formula tells you what the smallest whole number ratio between the that make up that compound is. In your case, you know that this contains...
1 Answers 1 viewsSince your compound will only contain sulfur and oxygen, you can conclude that the difference between the mass of sulfur and the mass of the final compound will represent the...
1 Answers 1 viewsYour goal when dealing with is to determine the smallest whole number ratio that exists between the that make up the compound. In order to do that, you first need...
1 Answers 1 views$"Moles of iron"$ $=$ $(2.561*g)/(55.85*g*mol^-1)$ $=$ $0.0459*mol$ $"Moles of sulfur"$ $=$ $(2.206*g)/(32.06*g*mol^-1)$ $=$ $0.0688*mol$ If we divide thru by the lower molar quantity, we get, $FeS_(1.5)$. However, by definition, the...
1 Answers 1 viewsMagnesium, Potassium, Lithium, and Sodium all have an oxidation state of $+1$. Calcium has $+2$. Oxygen and Sulfur have an oxidation state of $-2$. Fluorine and Chlorine have an oxidation...
1 Answers 1 viewsStart by assuming a mass of $100$ grams of the compound. Then, the percentages can be exchanged for masses. i.e. there are $"78 g"$ of cadmium and $"22 g"$ of...
1 Answers 1 viewsWe thus predict that hydrogen sulfide would have a formula of $H_2S$, an analogue of the popular $H_2O$ molecule.
1 Answers 1 viewsThe first step for any chemical reaction is to write out the chemical equation to determine the molar ratios of the reactants and products. Then we will use the molecular...
1 Answers 1 views