What is the mole fraction of $KCl$ in a mixture of 0.564g $NaCl$, 1.52g $KCl$ and 0.857g $LiCl$?

Md Ariful Islam

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Md Ariful Islam

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$"Mole fraction of component"$ $=$ $"Moles of component"/"Moles of all components"$

$"Moles of KCl"=(1.52*g)/(74.55*g*mol^-1)$ $=$ $0.0204*mol$

$"Moles of NaCl"=(0.564*g)/(58.44*g*mol^-1)$ $=$ $9.65xx10^-3*mol$

$"Moles of LiCl"=(0.857*g)/(42.39*g*mol^-1)$ $=$ $0.0202*mol$

$"Mole fraction of KCl"=(0.0204*mol)/((0.0202+0.00965+0.0204)*mol)$

$=$ $0.402$

Just as a check, the sum of fractions of all the components should give unity.

$"Mole fraction of NaCl"=(9.65xx10^-3*mol)/((0.0202+0.00965+0.0204)*mol)$

$=$ $0.192$

$"Mole fraction of LiCl"=(0.0202*mol)/((0.0202+0.00965+0.0204)*mol)$

$=$ $0.402$

The sum of the mole fractions do give unity as required.

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