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A 26.9-g sample of ammonium carbonate contains how many mol of ammonium ions?
The chemical formula for ammonium carbonate is $("NH"_4)_2"CO"_3"$. The formula indicates that in one mole of ammonium carbonate, there are two moles of ammonium ions, $"NH"_4"^+$. To calculate moles of...
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The formula for aluminum sulfate is $Al_2(SO_4)_3$. What is the molar mass of aluminum sulfate to the nearest gram?
The idea here is that the molar mass of aluminium sulfate, $"Al"_ 2("SO"_4)_color(blue)(3)$, will be equal to the sum of the molar masses of all the atoms that make up...
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What is the formula for ammonium sulfate?
$NH_4^+ + SO_4^(2-) -> (NH_4)_2SO_4 $
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How many atoms are there in a molecule of ammonium sulfate?
Formula of Ammonium sulphate $"= (NH"_4")"_2"SO"_4$ So, in a single molecule of Ammonium sulphate there are $2$ Nitrogen atoms $8$ Hydrogen atoms $1$ Sulphur atom $4$ Oxygen atoms...
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To make barium sulfate from 1 equiv barium nitrate, how many equiv of sodium sulfate are required?
$Na_2SO_4(aq) + Ba(NO_3)_2(aq) rarr BaSO_4(s)darr+ 2NaNO_3(aq)$ Barium sulfate is pretty insoluble stuff, and will precipitate from solution as a white solid. Its solubility in aqueous solution is negligible.
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How many moles of ammonium sulfate can be made from the 30.0 reaction of mol of $NH_3$ with $H_2SO_4$ according to $2NH_3 + H_2SO_4 -> (NH_4)_2SO_4$?
as per balanced equation we know 2moles ammonia produces 1 mole ammonium sulfate . hence 30 moles will produce 15 moles
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For the reaction,$2x$+$3y$+$4z$$ rarr$$ 5w$
Initially if 1 mole of $x$,3 mole of $y$ and 4 mole of $z$ is taken and 1.25 mole of $w$ is obtained then what is the % yield of this reaction?
This is a limiting reactant problem. We know that we will need a balanced equation and moles of each reactant. 1. Gather all the information in one place with...
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How many grams of ammonium sulfate are needed to make a 0.25 L solution at a concentration of 6 M?
Your strategy here will be to use the volume and of the solution to determine how many moles of ammonium sulfate, $("NH"_4)_2"SO"_4$, it must contain. Once you know...
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A 0.67 L solution of ammonium sulfate, $(NH_4)_2SO_4$ contains 0.81 mole of the solute. What is the approximate molarity of the solution?
If you look up the formula for , you will find this: $Molarity = (mol) / (liters)$ or $M = n/V$ So you are given : V = 0.67...
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Ksp=2.4x10^-5 for calcium sulfate.
What is the molar solubility of calcium sulfate in pure water?
What is the mass solubility of calcium sulfate in pure water,
expressed in g/L?
(a) Calcium sulfate is sparingly soluble. In a saturated solution the aqueous ions are in equilibrium with the insoluble salt: $sf(CaSO_(4(s))rightleftharpoonsCa_((aq))^(2+)+SO_(4(aq))^(2-))$ For which $sf(K_(sp)=[Ca_((aq))^(2+)][SO_(4(aq))^(2-)]=2.4xx10^(-5)color(white)(x)"mol"^2."l"^-2)$ The solubilty $sf(s)$ of the salt...
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