This is called the of the element. To make it up to 13 in carbon-13, you will need 7 neutrons. Stable isotopes are not useful at all in radio-dating,...
So, $"moles of carbon"$ $=$ $(26" carat"xx0.200*g*"carat"^-1)/(12.011*g*mol^-1)$. We mutliply this molar quantity by $"Avogadro's number ", 6.022xx10^23*mol^-1$, to give the number of carbon atoms.
$"1 carat"$ $=$ $"200 mg"$ $"Number of moles"$ $=$ $"Mass"/"Molar mass"$ $"Number of moles of carbon"$ $=$ $(3.25 cancel" carat"xx200xx10^-3*cancelg*cancel"carat"^-1)/(12.011*cancelg*mol^-1)$ $=$ $0.054*mol$, and we mulitply this by $"Avogadro's number"$...
The idea here is that you need to use the amount of hydrogen and the amount of carbon found in the $"5.0-g"$ sample of this unknown compound to determine the...
$"No. of moles"$ $=$ $"mass"/"molar mass"$ $=$ $("22 carat"xx200*mg*"carat"^-1)/(196.97*g*mol^-1)$ $=$ $??mol$ And $"number of gold atoms"$ $=$ $("22 carat"xx200xx10^-3g*"carat"^-1)/(196.97*g*mol^-1)xx6.022xx10^23*mol^-1$, which gives a result as a NOOMBER!
The answer relates to the stoichiometric equation, which tells us that $159.7*g$ $Fe_2O_3$ reacts with $84.0*g$ $CO$ to give $112*g$ $Fe$. You have $150*"lbs"xx454*g*"lb"^-1$ $=$ $68,100*g$ $Fe_2O_3$. Given the equations...
We're asked to find the volume (in liters) of $100%$ fruit juice that must be added to $1$ $"L"$ of a $10%$ fruit juice mixture so that the final concentration...
