The independent variable of an experiment is the thing you change. In this case, what we are changing will be the temperature. This will allow us to find the...
1 Answers 1 viewsAll you have to do here is make sure that the chemical equation that describes this decomposition reaction obeys the . Azomethane, $"C"_2"H"_6"N"_2$, is said to decompose to form...
1 Answers 1 viewsHow would you remove the half coefficient on the oxygen? What does the $Delta$ symbol mean here?
1 Answers 1 viewsThe equation $2Hg+O_2->2HgO$ is under the form of: $"Element "+" Element"->Product$ which is the general form of a synthesis reaction. It is similar to $2H_2+O_2->2H_2O$ for the synthesis of water.
1 Answers 1 viewsReddish Mercury(II)oxide solid is decomposed (broken down) upon heating into silver liquid mercury and colourless oxygen gas. The full balanced chemical equation is $2HgO->2Hg+O_2$
1 Answers 1 viewsHydrogen peroxide, $H_2O_2$ (very slowly) decomposes naturally into water and oxygen gas. $2H_2O_2(l)->2H_2O(l)+O_2(g)$ This is an exothermic reaction, so heat is also evolved.
1 Answers 1 viewsShe got $60*g$ of mercury metal....this represents a molar quantity of $(60*g)/(200.6*g*mol^-1)=0.299*mol$ with RESPECT to the metal. And thus there were $0.299*mol$ with respect to mercuric oxide... $HgO(s) + Delta...
1 Answers 1 viewsStart by writing the unbalanced chemical equation that can describe this decomposition reaction. $"Mg"("HSO"_ 3)_ (2(s)) -> "X"_ ((s)) + "H"_ 2"O"_ ((g)) + "SO"_ (2(g))$ Now, focus...
1 Answers 1 viewsThe idea is to see how many mols of $"H"_2$ you would have made in one reaction and reuse that value in the context of the other reaction. Assuming you...
1 Answers 1 viewsStart by taking a look at the thermochemical equation given to you $1/2"O"_ (2(g)) + "Hg"_ ((l)) -> "HgO"_ ((s))" "DeltaH = -"90.8 kJ"$ This equation tells you...
1 Answers 1 views