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We need a chemical equation:

$H_2O_2(aq) rarr H_2O(aq) + 1/2O_2(g)uarr$

Mass and charge are balanced as they must be (why; what do I mean here?). This is in fact a disproportionation reaction because the $O(-I)$ in peroxide, has been reduced to water $O(-II)$, and oxidized to zerovalent oxygen gas $O_2(0)$.

At any rate, the decomposition clearly features the breaking of $O-O$ bonds, and the formation of $O=O$ bonds; this is manifestly a chemical change.

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