involve a formal change in oxidation number........
And if we superscript the ..........
The metal has been (typically) oxidized, and has donated electrons to the non-metal, and thus reduced it..........
Can you write the individual half equations representing formal oxidation and reduction?
We need a stoichiometric equation that represents the reaction between $Mg(OH)_2$ and $HCl$, and here it is............ $Mg(OH)_2(s) + 2HCl(aq) rarr MgCl_2(aq) + 2H_2O(l)$ Here, $1$ $"equiv"$ of magnesium hydroxide...
1 Answers 1 viewsAlumina is $Al_2O_3$, which is the product of aluminum oxidation. None of your equations shows the correct formulae. We can rewrite the correct equation as: $2Al(s)+ 3/2O_2(g) rarr Al_2O_3(s)$ This...
1 Answers 1 viewsYou have to search the between Na and $Cl_2$ You have $ n= "mass"/"molecular mass" = (103,0 g)/(23,0 (g/(mol))) = 4,47 mol $ of Na. As 1 mole occupies 22,4...
1 Answers 1 viewsWe must first identify the limiting reactant, and then we calculate the theoretical yield and percent yields. We start with the balanced equation. $color(white)(mmmmmmmm)"4HCl" + "O"_2 → "2H"_2"O" +...
1 Answers 1 viewsYOu have been given the chemical equation: $H_2(g) + Cl_2(g) rarr 2HCl(g)$ There are 2 equiv (moles if you like) of gaseous product, and 2 equiv gaseous reactant. Clearly, mass...
1 Answers 1 viewsYour strategy here will be to use the molar mass of magnesium chloride to determine how many moles you would have in that sample use...
1 Answers 1 viewsWell, I would never recommend this "trial-and-error" method... I don't see why you should ever "have" to do it... just use the quadratic formula on the resulting quadratic equation. I...
1 Answers 1 views$HCl(aq)+H_2O(l)rarr Cu^(2+) + 2NO_3^-$ $Ca(OH)_2(s) stackrel(H_2O)rarr Ca^(2+) +2HO^-$ $Ca(NO_3)_2(s) stackrel(H_2O)rarr Ca^(2+) +2NO_3^-$ $NH_3(aq) +H_2O(l) rightleftharpoonsNH_4^+ + HO^-$ And one of these things is not like the other ones.........
1 Answers 1 viewsAmmonia is a Bronsted base: $NH_3(aq) + H_2O(l) rightleftharpoons NH_4^+ + OH^-$ $pK_b = 4.75$ I am not going to solve this equation using $pK_b$, but most of the ammonia...
1 Answers 1 viewsThe standard of formation is the enthalpy associated with the formation of 1 mole of substance from its constituent in their standard states under specified conditions. And of course...
1 Answers 1 views