We need a stoichiometric equation that represents the reaction between $Mg(OH)_2$ and $HCl$, and here it is............ $Mg(OH)_2(s) + 2HCl(aq) rarr MgCl_2(aq) + 2H_2O(l)$ Here, $1$ $"equiv"$ of magnesium hydroxide...
$2H_2(g)+O_2(g) rarr 2H_2O(l)$ $36*g$ of reactants, and $36*g$ of products.......... VERSUS....... $H_2(g) + 1/2O_2(g)rarr H_2O(l)$ $18*g$ of reactants, and $18*g$ of products.......... Is mass conserved in each reaction? Well, clearly...
Alumina is $Al_2O_3$, which is the product of aluminum oxidation. None of your equations shows the correct formulae. We can rewrite the correct equation as: $2Al(s)+ 3/2O_2(g) rarr Al_2O_3(s)$ This...
$C_3H_8(g) + 5O_2(g)rarr3CO_2(g) + 4H_2O(g)$ The stoichiometric equation CLEARLY specifies that $"1 mol"$ ($44*g$) of propane reacts with $"5 moles"$ ($160*g$) of dioxygen to give $"3 moles"$ ($132*g$) of carbon...
We can use to find the moles of $Mg(NO_3)_2$ and then the respective grams of $Mg(NO_3)_2$. If 8 moles of water are produced, we can find out how many moles...
We need a stoichiometic equation: $SO_2(g) + 1/2O_2(g) rarr SO_3(g)$ The equation unequivocally tells us that the reaction of $64*g$ $SO_2(g)$ with $16*g$ $O_2(g)$ gives $80*g$ $SO_3(g)$. The given masses...
Start with the balanced equation. $"4Fe(s) + 3O"_2("g")$$rarr$$"2Fe"_2"O"_3"$ Determine the molar masses of oxygen gas and iron using their atomic masses from in g/mol. $"O"_2:$$(2xx15.998 "g/mol")="31.998 g/mol"$ $"Fe":$$"55.845 g/mol"$ Now...
$HCl(aq)+H_2O(l)rarr Cu^(2+) + 2NO_3^-$ $Ca(OH)_2(s) stackrel(H_2O)rarr Ca^(2+) +2HO^-$ $Ca(NO_3)_2(s) stackrel(H_2O)rarr Ca^(2+) +2NO_3^-$ $NH_3(aq) +H_2O(l) rightleftharpoonsNH_4^+ + HO^-$ And one of these things is not like the other ones.........
Ammonia is a Bronsted base: $NH_3(aq) + H_2O(l) rightleftharpoons NH_4^+ + OH^-$ $pK_b = 4.75$ I am not going to solve this equation using $pK_b$, but most of the ammonia...
The standard of formation is the enthalpy associated with the formation of 1 mole of substance from its constituent in their standard states under specified conditions. And of course...