Share with your friends
Call

In such a mass, there are $2xxN_A$ $"nitrogen atoms"$, and

$8xxN_A$ $"hydrogen atoms"$, and

$2xxN_A$ $"chromium atoms"$, and

$7xxN_A$ $"oxygen atoms"$.

Here we use $N_A$ as a counting number, i.e. as we would use the number $10$, or a $"million"$, or a $"dozen"$.

Talk Doctor Online in Bissoy App