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Which type of bonding accounts for the relatively high boiling point of $H_2O$ as compared with the relatively low boiling point of $H_2S$?
Hydrogen bonding is an intermolecular force that operates between molecules where hydrogen is bound to a strongly electronegative element such as fluorine or nirogen. Hydrogen sulfide has some (little) degree...
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$H_2O$ forms a tetrahedral shape due to the two lone pairs. Why can't this rule be applied to all molecules with lone pairs?
You are absolutely right that the lone pairs are stereochemically active, and influence geometry, however, the lone pairs are simply along for the ride. If you consider the chloride ion,...
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If an atom of nitrogen binds with three hydrogen atoms to form a molecule of ammonia, how many lone pairs of electrons does nitrogen have?
There are 4 electron pairs around the nitrogen atom: $3xxN-H$ bonds, and one nitrogen-centred lone pair. The lone pair is stereochemically active (and hence $NH_3$ is a trigonal pyramid, but...
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What is the molecular shape of a hydrogen sulfide molecule, $H_2S$?
Sulphur has 6 , of which two are involved in the formation of the two S-H bonds. This leaves two lone pairs, which prevent the electrons from forming a linear...
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The electron pair geometry of a molecule is tetrahedral. What is its bond angle if it shows one lone pair of electrons and three bonding pairs?
predicts that the electron pairs will be arranged in a tetrahedron. However, because we describe the geometry on the basis of the disposition of atoms, not electron pairs, the...
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The $PH_3$ molecule can be represented in a tetrahedral arrangement similar to $NH_3$. How does one $PH_3$ molecule interact with other $PH_3$ molecules?
For the ammonia molecule, there is a large difference in between the hydrogen and nitrogen nuclei, and the nitrogen atom polarizes electron towards itself, $""^(delta-)N-H^(delta+)$. The result? Intermolecular hydrogen bonding...
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How does elemental phosphorus react to give $PH_3$ and $HPO_2^(-)$ under basic conditions?
$1/4P_4+3H^+ + 3e^(-) rarrPH_3$ $"(i) reduction"$ $1/4P_4 + 2HO^(-) rarr HPO_2^(-) +H^(+) + 2e^(-)$ $" (ii) oxidation"$ Overall: $2xx(i) + 3xx(ii)$ $5/4P_4+6H_2O rarr2PH_3 +3HPO_2^(-) +3H^(+)$ I will add $3xxHO^-$ to...
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In the reaction $H_2S + 2O_2 -> H_2SO_4$, the law of definite proportions predicts that for every mole of $H_2S$, you will need how many moles of $O_2$?
I would look at your equation again. You have even balanced and formatted it properly. What does it say? It says 1 molecule of hydrogen sulfide reacts with 2 molecules...
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What is the maximum number of grams of $PH_3$ that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form $PH_3$?
Start with a balanced equation. $"P"_4 + "6H"_2"$$rarr$$"4PH"_3"$ This is a limiting reactant problem. The reactant that produces the least $"PH"_3"$ determines the maximum number of grams of $"PH"_3"$ The...
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If 5.04 grams of iron (II) nitrate reacts with an excess of $H_2S$, what mass of iron(II) sulfide will be produced in the reaction $Fe(NO_3)_2 + H_2S -> FeS + H(NO_3)$?
$Fe(NO_3)_2(aq) + H_2S(aq) rarr FeS(s)darr + 2HNO_3(aq)$ The stoichiometrically balanced equation tells you explicitly that 1 mol of sulfide will result from every mole of ferrous nitrate. $"Moles of ferrous...
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