since this is a dehydration reaction, it means that when two molecules are linked together, there will be one molecule of water $H_2O$ removed.
Therefore, the molecular formula will be $C_18H_32O_16$.
The reaction will be: $C_6H_11O_5-underbrace(OH+H)_(color(blue)(H_2O))-C_6H_10O_5-underbrace(OH+H)_(color(blue)(H_2O))-C_6H_11O_6->C_18H_32O_16+color(blue)(2H_2O)$
We have the balanced chemical equation: $6CO_2(g)+6H_2O(l)->C_6H_12O_6(aq)+6O_2(g)$ So, we see that six molecules of carbon dioxide produce one molecule of glucose, and that's the ratio between those two products and...
I think the molecules of $"ATP"$ produced is closer to $36$, but anyway... $color(white)(---)$ If $"1 glucose"$ gives us $"30 ATP"$ molecules, then we can set up the relationships as...
$C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(g)$ Moles of glucose, $=$ $(8.064*cancel(g))/(180.16*cancel(g)*mol^-1)$ $=$ $4.476xx10^-2$ $mol$. From the equation above, there will be approximately 0.8 g water produced.
$"C"_6"H"_12"O"_6" + 6O"_2"$$rarr$$"6CO"_2" + 6H"_2"O"$ Molar Masses of Glucose and Water $"C"_6"H"_12"O"_6":$$"180.15588 g/mol"$ $"H"_2"O":$$"18.01528 g/mol"$ Divide $"8.064 g"$ of glucose by its molar mass to get moles glucose....
...and more symbolically, $RCH_2CH_2OHstackrel(Delta)rarrRCH=CH_2 + H_2O$ The formation of water serves as a thermodynamic driving force to the reaction....
Polymerisation by step growth involving condensation reactions where the molecular group eliminated is water are sometimes referred to as "dehydration synthesis" reactions. For example, the formation of polyesters via the...
We have the balanced equation (without state symbols): $6H_2O+6CO_2->C_6H_12O_6+6O_2$ So, we would need six moles of carbon dioxide to fully produce one mole of glucose. Here, we got $88 \...