Either name is still commonly used. Of course, it is formulated on the basis of electrical neutrality. 2 equiv $Fe^(3+)$, the ferric ion, and 3 equiv $SO_4^(2-)$ give a neutral charge.
Here, we use as we would use any other collective number: a dozen eggs; a Bakers' dozen; a Botany Bay dozen. Of course, the mole specifies a much larger quantity,...
It is given that both salts contain the same number of sulfur atoms. Thus we have $Al_2S_3O_12$, and necessarily $3$ $xx$ $H_2SO_4$. There are $3$ $"equiv"$ sulfuric acid per equiv...
Simply cancel out the common items, the ones that do not undergo chemical change in the original equation: $2Fe^(3+) + cancel(6Cl^(-) + 6Na^(+)) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr +cancel(6Na^(+) + 6Cl^(-))$...
The electron configuration for iron, $Fe$ is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2$ The orbital filling order for $Fe$ is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^6$ Iron does...
Let's eliminate unknowns backwards, starting with $G$. From the equations for $H$, $Mn$, $K$ and $Fe$ we find: $G=C$ $F=B$ $E=1/2 B$ $D=1/2 A$ Substituting these in the...
Water has a $3$ coeeficient. Is the equation stoichiometrically balanced? If not, then it should be. The oxide ion is dibasic, and reacts with 2 equiv $H^+$ to give the...
Start by looking at the most complex compound, and balancing around that. In this case, its $Fe_2(SO_4)_(3(aq))$. We see that we need 2 Fe and 3 $SO_4$ on the...
So we approach the equation by the method of half equations: $Fe(III)$ is reduced to $Fe(II)$: $Fe^(3+) + e^(-)rarrFe^(2+)$ $(i)$ And $"oxalate ion"$ is oxidized to $CO_2$: $C_2O_4^(2-) rarr 2CO_2...
Since aluminium sulphate is in excess, it implies that sodium hydroxide is the limiting reactant and decides how much product is formed as it gets used up first. The balanced...
Balanced Equation $"3Ba + Al"_2"(SO"_4)_3"$$rarr$$"2Al + 3BaSO"_4$ The coefficients are the moles of each substance, and they can be used as molar ratios between two of the substances. No coefficient...
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