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Of course, in hydroxides $O$ formally has a $-II$ oxidation state, whereas in hydrogen peroxide, $HO-OH$ (or peroxide dianion, $O-O^(2-)$, the oxygen bears an $O-O$ linkage; that is it formally has a $-I$ oxidation state . The peroxide bond is weak as bonds go, and cleavage of the $O-O$ can readily occur, as shown in the following equation:

$H_2O_2 rarr 2HO*$. This hydroperoxide radical, $HO*$, is neutral and very reactive.

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