The idea here is that each isotope will contribute to the average of the element proportionally to their respective abundance. Now, the key to this problem lies in how you...
1 Answers 1 viewsTo find the average ($"A"_r$) of an element, given the percentage rarities of its , simply multiply each isotope's $"A"_r$ by its percentage that is expressed as a decimal...
1 Answers 1 viewsMultiply the atomic mass of each isotope times its percent abundance in decimal form. Add them together. $"Average atomic mass of Br"$$=$$(78.92xx0.5069)+(80.92xx0.49331)="79.92 u"$
1 Answers 1 viewsWe know that: $x_(1)106.9059 + x_(2)108.9047 = 107.8682$ $(i)$ $x_(1) + x_(2) = 1$ $(ii)$ We assume that silver has only the 2 , which for a first approximation...
1 Answers 1 viewsThe weighted average is the sum of each individual nuclide, multiplied by its isotopic abundance. So, we simply do the arithmetic: $0.7577xx34.969+0.2423xx36.966 = ???$ amu Then look at to...
1 Answers 1 viewsAs you know, the average of an element is calculated by taking the weighted average of the atomic masses of its naturally occurring . In simple terms, each...
1 Answers 1 viewsThe molar mass of an element is its atomic weight (relative atomic mass) on in g/mol. Molar masses $"Cl":$$"35.45 g/mol"$ $"Al":$$"26.98 g/mol"$ The molar mass is the mass of one...
1 Answers 1 viewsThe $"Average Atomic Mass"$ of an element is defined as "the weighted average mass of all naturally-occurring (occasionally radioactive) of the element." (and hence the name "average") [1] Dividing the...
1 Answers 1 viewsUsing my (not very precise) periodic table, I get the mass of Ag as 107.87. This must be a combination of these two . So the % of the other...
1 Answers 1 viewsThe average of some substance is measured indeed with the percentages of how much they exist in nature. An average is always calculated by adding up the numbers and divide...
1 Answers 1 views