$color(white)(XX)$mass(amu)$color(white)(X)$Isotopic abundance
Br-79$color(white)(XXXX)$78.92$color(white)(XXXXXXX)$?
Br-81$color(white)(XXXX)$80.92$color(white)(XXXXXXX)$?
$"average atomic mass"=("mass*%"+"mass*%"+"mass*%"...)$
Let x be % abundance of Br-79
Let 1-x be % abundance of Br-81
Br is 79. 904g/mol on $color(orange)"(average atomic mass)"$
$79.904%=x+(1-x)$
$79.904%=(78.92*x)+(80.92*(1-x))$
$79.904%=(78.92x)+(80.92-80.92x))$
$79.904%=78.92x+80.92-80.92x$
$79.904%=-2x+80.92$
$79.904%-80.92=78.92x$
$-1.016=-2x$
$x=0.508$
Use our x to find that % abundance of Br-79
$x*100%$
$0.508*100%$
$=50.8$ $"%$ $abundance"$
Use our x to find that % abundance of Br-79
$(1-x)*100%$
$0.492*100%$
$=49.2$ $"%$ $abundance"$
$:.$ The % abundance of the isotope with a mass of 78.92 amu has a % abundance of 50.8% and the isotope with a mass 80.92 amu has a % abundance of 49.2%