On a certain day toronto, canada, the temperature was 15 degrees celsius(C). Using the formula F= 9/5 C+32, Peter converts this temperature to degrees Fahrenheit (F). Wich temperature represents 15 degrees Celsius in degrees Fahrenheit?

The formula is $"F" = 9/5"C + 32"$ Hence, $"F" =9/5×38.0 + 32 = 100.4$ The above formula ignores units. Here it is with units. $"F" = 38.0 color(red)(cancel(color(black)("°C")))...

To convert Fahrenheit to Celsius, the normal method is to subtract $32$ then divide by $1.8$ (i.e. $9/5$). So in our example: $5/9(70-32) = 5/9(38) = 190/9 = 21.bar(1)$...

We can convert from Fahrenheit to Celsius using the formula: $c = 5/9(f-32)$ or from Celsius to Fahrenheit using the formula: $f = 9/5c + 32$...

The formula is $F = 9/5C + 32$ $F$ increases as $C$ increases and $F$ decreases as $C$ decreases, but the relation is not a direct proportionality. In mathematics,...

$"Temperature "=$ $104$ $""^@F$ I don't think I can explain the conversion better than this It does have links to auto-converters. The 3 Fahrenheit temperatures that I tend...

The freezing point of water is 0 degrees Celsius. If chocolate melts at 22 degrees Celsius, then it is 22 degrees higher than the freezing point of water.

If you notice that $1.8=18/10$ then this can be done (or almost done) in your head: $18/10*25+32$ $color(white)("XXX")=18/2*5+32$ $color(white)("XXX")=9*5+32$ $color(white)("XXX")=45+32$ $color(white)("XXX")=77$

I believe you would just need to add both of the temperatures together to get the difference since one of them is below zero.

The ratio of degree's C to degrees F is 9/5 freezing to boiling for C is from 0 to 100 a change of 100 freezing to boiling for...

The Fahrenheit freezing point of water is $32^@"F"$ and its boiling point is $212^@"F"$. $212^@"F" -32^@"F" = 180^@"F"$ between the freezing point and boiling point of water. The Celsius freezing...