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How would you convert parsecs to centimeters?
We should not use such small measures for such large distances that's why we use light years and Parsecs where huge distances are involved usually on cosmic scale. Anyways 1...
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What would happen if you brought a piece of the center of the sun the size of a basketball back to earth? What would happen to the living things around it, and if you dropped it, would it burn through the ground into the earth?
Take a look at a wiki article on the .
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How many Joules are in 2.5 kcal?
Remember that $"1 kcal"$ $=$ $"1 Cal"$ $ne$ $"1 cal"$, so this is the one where: $"4.184 J"$ $=$ $"1 cal"$. Therefore: $=> "2.5" cancel("k")cancel("cal") xx (1000...
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How would you convert $g/(cm^3)$ to $mL$?
If you meant $"g/mL"$, then it requires little effort. $"1 cm"^3$ is known to be equivalent to $"1 mL"$, so you're done. If you meant $"mL"$, it's not the same...
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How would you convert $1.54×10^ -10$ L into mL?
$1.54xx10^-10*L$ $=$ $1.54xx10^-10*cancelLxx10^3*mL*cancel(L^-1)$ $=$ $1.54xx10^-7*mL$ If $1*muL$ $=$ $10^-6*L$, how many $"microlitres"$ does the answer represent?
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How would you convert 9 grams to decigrams?
And thus $9*g=(9*cancelg)/(10^-1*cancelg*"decigram"^-1)=(9)/((1/10)(1/"decigram"))$ $=90*"decigram................."$
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Why can't you just convert meters cubed to mL >> then >> convert mL to Liters? Giving: 0.019L (after Sig Figs)?? This references the video "Converting Metric Units of Volume."
A cubic metre is a HUGE volume. And $1*cm^3-=1*mL=10^-3*L$. These are all common units of volume in the laboratory. In Europe, we buy milk in litres, and in England, sometimes...
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How do you convert 1.41 kcal to joules?
$"1 calorie"-=4.184*"Joule"$ And thus.....$1.41*kcal-=1.41xx10^3*calxx4.184*J*cal^-1$ $=5899.4*J-=5.90*kJ$....
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How do you complete the following equation to illustrate the first ionization energy for one mole of magnesium atoms: $Mg:(g) + ? kcal -> Mg(g) + e^-$
All science relies on data, and to get these data, we need measurement. I don't know how they measure the ionization energy of magnesium metal, but I know that it...
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How do you calculate the energy required to produce 7.00 mol $Cl_2O_7$ on the basis of the following balanced equation: $2Cl_2(g) + 7O_2(g) + 130 kcal -> 2Cl_2O_7(g)$?
You gots... $2Cl_2(g) + 7O_2(g) + 130*kcal rarr 2Cl_2O_7(g)$ Another way of writing this is as... $2Cl_2(g) + 7O_2(g) rarr 2Cl_2O_7(g)$ $DeltaH_"rxn"^@=+130*kcal*mol^-1$ And when we write $mol^-1$ we mean per...
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