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The comet follows an elliptical orbit according to Kepler's laws. Given the semi-major axis distance $a$ and the eccentricity $e$. The perihelion distance is:

$a(1-e)=2$

Te aphelion distance is:

$a(1+e)=86$

Adding the equations gives:

$2a=88$

Dividing by 2 gives the semi-major axis distance $a=44$AU.

Kepler's third law relates the period $T$ in years to the semi-major axis $a$ in AU:

$T^2=a^3=44^3$

Cubing and taking the square root gives $T=291.86$ years.

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