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Use $v=sqrtmu((2/r)-(1/a))$, perihelion = $a(1-e)$ and aphelion $= a(1+e)$.

Here e = 0.25, approximately.

Now, for any planet, the ratio of the speeds at perihelion and aphelion becomes

$sqrt((1+e)/(1-e))$ and here it is $sqrt( 1.25/0.75)=sqrt(5/3)$.

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